2x^2=195

Solution for 2x^2=195 equation:

2x^2=195

We move all terms to the left:

2x^2-(195)=0

a = 2; b = 0; c = -195;
Δ = b2-4ac
Δ = 02-4·2·(-195)
Δ = 1560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1560}=\sqrt{4*390}=\sqrt{4}*\sqrt{390}=2\sqrt{390}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{390}}{2*2}=\frac{0-2\sqrt{390}}{4}
=-\frac{2\sqrt{390}}{4}
=-\frac{\sqrt{390}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{390}}{2*2}=\frac{0+2\sqrt{390}}{4}
=\frac{2\sqrt{390}}{4}
=\frac{\sqrt{390}}{2}
$